Question of the Day

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6/1

Dec
2
2012
210,817 responses
Question of the Day Statistics
Number Answered
Correct 81,354
Incorrect 129,463
38% correct

Mathematics > Standard Multiple Choice

Read the following SAT test question and then click on a button to select your answer. 

The stopping distance of a car is the number of feet that the car travels after the driver starts applying the brakes. The stopping distance of a certain car is directly proportional to the square of the speed of the car, in miles per hour, at the time the brakes are first applied. If the car’s stopping distance for an initial speed of 20 miles per hour is 17 feet, what is its stopping distance for an initial speed of 40 miles per hour?

Answer Choices

Hint

The stopping distance is directly proportional to the square of the initial speed of the car. If s represents the initial speed of the car, in miles per hour, and d represents the stopping distance, you have that the stopping distance is a function of s and that function d of s = c times (s^2), where c is a constant.

Question of the Day

Can you answer today's question?

Register Next Tests:
6/1

Dec
2
2012
210,817 responses
Question of the Day Statistics
Number Answered
Correct 81,354
Incorrect 129,463
38% correct

Mathematics > Standard Multiple Choice

Read the following SAT test question and then click on a button to select your answer. 

The stopping distance of a car is the number of feet that the car travels after the driver starts applying the brakes. The stopping distance of a certain car is directly proportional to the square of the speed of the car, in miles per hour, at the time the brakes are first applied. If the car’s stopping distance for an initial speed of 20 miles per hour is 17 feet, what is its stopping distance for an initial speed of 40 miles per hour?

Answer Choices

Answer

The stopping distance is directly proportional to the square of the initial speed of the car. If s represents the initial speed of the car, in miles per hour, and d represents the stopping distance, you have that the stopping distance is a function of s and that function d of s = c times (s^2), where c is a constant. Since the car’s stopping distance is 17 feet for an initial speed of 20 miles per hour, you know that 17 = c times 20^2. Therefore, c = 17 over 20^2 = 0.0425, and the car's stopping distance for an initial speed of 40 miles per hour is 0.0425 times 40^2 = 68 feet.